Question

How do you find the derivative of `g(x)=3x-1`?

Answer 1

`g'(x) = 33`

Explanation:

We use the power rule for derivatives:

`d/dx x^n=nx^(n-1)`

Which for:

`g(x) = 3x-1 \ \ (=3x^1-1x^0)`

gives:

`g'(x) = 3 - 0 = 3`