To solve this, we use the formula for heat absorption, Q = mTc, where
Q is the heat energy absorbed, in Joules,
m is the mass of the object usually in grams,
T is the temperature change of the object, in Celcius or Kelvin, and
c is the specific heat capacity of the material, in joules per gram °C. This is the amount of energy it takes for one gram of this substance to heat up by 1K.
We then rearrange this equation making m the subject:
m = Q/(Tc)
The question gives us the values Q = 1kJ = 1000J, and we can calculate T by using
T = "Final Temperature" - "Initial Temperature" = 41.8"°C" - 33.0"°C"
T = 8.80"°C = 8.80K"
Now the only remaining value we need is c. Since this depends on the material involved, we have to look up the value for silver.
I found 3 sources: hyperphysics, periodictable.com, and ptable.com.
These put the value at 0.233Jg^-1K^-1, 0.235Jg^-1K^-1, and 0.235Jg^-1K^-1 respectively. I will use 0.235Jg^-1K^-1 here.
Now we substitute into the equation:
m = Q/(Tc) = (1000J)/(8.80K xx 0.235Jg^-1K^-1) = 484g " (3 s.f.)"
If you have been given a value for the specific heat capacity of silver which is not 0.235Jg^-1K^-1, then your final answer may be slightly different.
