What is the Cartesian form of #(-10,(13pi)/16)#?

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Answer 1 · 2017-04-15T18:31:45

#(8.315,5.556)#

Use the parametric form to find the #x# and #y# points. To convert from polar to parametric form, use these equations:

#x(t)=rcos(theta)#

#y(t)=rsin(theta)#

From our point, we can see that #r=-10# and #theta=13pi/16#. Plug into our formulas:

#x(13pi/16)=-10cos(16pi/16)~~8.315#

#y(13pi/16)=-10sin(16pi/16)~~-5.556#

So our point is #(8.315,5.556)#