Question

What is the derivative of `y= ln(2x)/x^2`?

Answer 1

`dy/dx=(1-2ln(2x))/x^2`

Explanation:

Use quotient rule and chain rule :

`dy/dx=(2(1/(2x))(x^2)-(ln(2x)(2x)))/x^4`

Simplify:

`dy/dx=(x-ln(2x)(2x))/x^4`

Take out a `x` from the numerator and denominator:

`dy/dx=(1-2ln(2x))/x^2`