Question

Question #57682

Answer 1

See below

Explanation:

`y=arcsin(cot(x^-2))`

`siny=cot(x^-2)`

`(cosy)y'=-(2csc^2(x^-2))/x^3`

`y'=-(2csc^2(x^-2))/(x^3cosy)`

`cosy=+-sqrt(1-sin^2y)=+-sqrt(1-cot^2(x^-2))`

`y'=+-(2csc^2(x^-2))/(x^3sqrt(1-cot^2(x^-2)))`