Question

How do you find the domain of `f(x)=x/(x^2+1)`?

Answer 1

The domain is `=RR`

Explanation:

The denominator is `(x^2+1)`

`AA x in RR, (x^2+1)>0`

So, the domain of `f(x)` is

`D_f(x)=RR`

graph{x/(x^2+1) [-10, 10, -5, 5]}