How do you solve 3^ { 3r - 1} = 3^ { - 2r - 3}33r−1=3−2r−3?
2 Answers
Apr 16, 2017
In the given eqn, the bases are equal, so equate powers on both sides.
Explanation:
Apr 16, 2017
Explanation:
Since the
color(blue)"bases on both sides of the equation are 3"bases on both sides of the equation are 3 we can equate the exponents.
rArr3r-1=-2r-3⇒3r−1=−2r−3
rArr5r=-2⇒5r=−2
rArrr=-2/5⇒r=−25
color(blue)"As a check"As a check
3^((-6/5-5/5))=3^(-11/5)3(−65−55)=3−115
"and " 3^((4/5-15/5))=3^(-11/5)and 3(45−155)=3−115
rArrr=-2/5" is the solution"⇒r=−25 is the solution