Question

What is K if `DeltaG^@` = -18.0 kJ for a reaction at 25 degrees C?

Answer 1

`sf(K=6.97xx10^(-4))`

Explanation:

`sf(DeltaG^@=-RTlnK)`

`:.` `sf(lnK=-(DeltaG^@)/(RT))`

`sf(lnK=-(18xx10^3)/(8.31xx298)=-7.268)`

`sf(K=6.97xx10^(-4))`