What is the Cartesian form of #( -7 , (25pi)/12 ) #?

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Answer 1 · 2017-04-16T20:19:13

#(-6.761,-1.811)#

Use the parametric form to find the #x# and #y#:

#x=rcostheta#

#y=rsintheta#

Plug into these formulas:

#x=-7cos(25pi/12)~~-6.761#

#y=-7sin(25pi/12)~~-1.811#

Now we have #x# and #y#. We just need to write them together:

#(-6.761,-1.811)#