How do you simplify $\frac{8 x^{5} - 10 x y^{2}}{2 x y^{2}}$ $(8x^5-10xy^2)/(2xy^2)$ and what are the excluded values of the variables?

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How do you simplify $\frac{8 x^{5} - 10 x y^{2}}{2 x y^{2}}$ $(8x^5-10xy^2)/(2xy^2)$ and what are the excluded values of the variables?

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Answer 1 · 2017-04-18T06:45:26

$= \frac{4 x^{4} - 5 y^{2}}{y^{2}} or = \frac{4 x^{4}}{y^{2}} - 5$ $=(4x^4-5y^2)/y^2" or "=(4x^4)/y^2 -5$

$x and y$ $xand y$ may not be $0$ $0$

Explanation:

The excluded values are any values that would make the denominator equal to $0$ $0$ , or any number that we use to divide.
$x and y$ $xand y$ may not be $0$ $0$

$\frac{8 x^{5} - 10 x y^{2}}{2 x y^{2}} \leftarrow$ $(8x^5 -10xy^2)/(2xy^2)" "larr$ factorise the numerator

$= \frac{2 x (4 x^{4} - 5 y^{2})}{2 x y^{2}}$ $=(2x(4x^4-5y^2))/(2xy^2)$

$=(cancel(2x)(4x^4-5y^2))/(cancel(2x)y^2)$

$=(4x^4-5y^2)/y^2$

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You could also split the fraction into two separate fractions:

$(8x^5)/(2xy^2) -(10xy^2)/(2xy^2)$

$=(4x^4)/y^2 -5$

This leaves two terms in the answer.

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How do you simplify $\frac{8 x^{5} - 10 x y^{2}}{2 x y^{2}}$ $(8x^5-10xy^2)/(2xy^2)$ and what are the excluded values of the variables?

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Explanation:

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How do you simplify $\frac{8 x^{5} - 10 x y^{2}}{2 x y^{2}}$ $(8x^5-10xy^2)/(2xy^2)$ and what are the excluded values of the variables?