How do you differentiate #5x^2-x^3siny+5xy=10#?
1 Answer
Apr 18, 2017
Explanation:
differentiate
#color(blue)"implicitly with respect to x"#
#"the terms " -x^3siny" and " 5xy" require to be differentiated using the " color(blue)"product rule"#
#rArr10x+(-x^3cosy.dy/dx-3x^2siny)+(5x.dy/dx+5y)=0#
#"factor out " dy/dx#
#dy/dx(-x^3cosy+5x)=3x^2siny-10x-5y#
#rArrdy/dx=(3x^2siny-10x-5y)/(5x-x^3cosy)#
