How do you solve #2 / 3 (x − 2) = 4x # and find any extraneous solutions?

1 Answer
EZ as pi
Apr 22, 2017

#x = -2/5#

Explanation:

Multiply both sides of the equation by #3/2#

#cancel3/cancel2 xxcancel2/cancel3(x-2) = 3/cancel2xx cancel4^2x#

#x-2 = 6x#

#-2 = 5x" "larr div 5#

#-2/5 =x#

#x# is not in the denominator and there are no restrictions on #x#, therefore there are no extraneous solutions.

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