Question #b256c

1 Answer
anor277
Apr 24, 2017

You have the stoichiometric equation:

Explanation:

#H_3PO_4 + 3KOHrarr K_3PO_4 + 3H_2O#.

#"Moles of KOH"# #=# #(89.5*g)/(56.11*g*mol^-1)=1.60*mol#

And thus, given the equation, #0.531*mol# #H_3PO_4# will react, i.e. #0.531*molxx98.08*g*mol^-1=52.1*g#.

Of course, there is a catch. In aqueous solution, phosphoric acid acts as a diacid, and NOT AS A TRIACID. Only 2 equiv of the potassium hydroxide will react to give #K^(+)""^(-)HPO_4(aq)#

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