How do you multiply (4m^2-2n)^2(4m22n)2?

1 Answer
Apr 24, 2017

See the solution process below:

Explanation:

To multiply this expression we can use this rule:

(a - b)^2 = a^2 - 2ab + b^2(ab)2=a22ab+b2

If we let: a = 4m^2a=4m2 and b = 2nb=2n and substitute we get:

(4m^2 - 2n)^2 = (4m^2)^2 - 2(4m^2)(2n) + (2n)^2 =(4m22n)2=(4m2)22(4m2)(2n)+(2n)2=

16m^4 - 16m^2n + 4n^216m416m2n+4n2

Another way to multiply this is to first rewrite the expression as:

(4m^2 - 2n)(4m^2 - 2n)(4m22n)(4m22n)

Then, to multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(color(red)(4m^2) - color(red)(2n))(color(blue)(4m^2) - color(blue)(2n))(4m22n)(4m22n) becomes:

(color(red)(4m^2) xx color(blue)(4m^2)) - (color(red)(4m^2) xx color(blue)(2n)) - (color(red)(2n) xx color(blue)(4m^2)) + (color(red)(2n) xx color(blue)(2n))(4m2×4m2)(4m2×2n)(2n×4m2)+(2n×2n)

16m^4 - 8m^2n - 8m^2n + 4n^216m48m2n8m2n+4n2

We can now combine like terms:

16m^4 + (-8 - 8)m^2n + 4n^216m4+(88)m2n+4n2

16m^4 + (-16)m^2n + 4n^216m4+(16)m2n+4n2

16m^4 - 16m^2n + 4n^216m416m2n+4n2