Question

What molar quantity of `HCl` is there in a `24.38*mL` volume of an aqueous solution that is `0.100*mol*L^-1` with respect to `HCl`?

Answer 1

Approx. `25xx10^-4*mol`.

Explanation:

We use the relationship:

`"Concentration"` `=` `"Moles of solute"/"Volume of solution"`,

And typically, because we often use units of `"litres"` to express volume, `"concentration"` has units `"moles"*"L"^-1`.

And thus to assess the number of moles in a `24.38*mL` volume of `0.100*mol*L^-1` `HCl`, we simply assess the product:

`"Moles of solute"` `=` `"Concentration "xx" volume"`

`=24.38xx10^-3*cancelLxx0.100*mol*cancel(L^-1)=24.38xx10^-4*mol`.

And we need an equimolar quantity of `NaOH` to neutralize this molar quantity.