Question

Question #4eb61

Answer 1

Mass `Al_2O_3` produced = 85 grams.

Explanation:

For reaction problems, convert all givens to moles and apply to rxn ratios of balanced equation.

`4Al^o(s)`........... +........ `3O_2(g)` => `2Al_2O_3(s)`
4moles ......................(excess) ..... 2moles

(45g/27g/mol)......................... => ...1/2(1.7mol)`Al_2O_3(s)`
= 1.7 mole `Al^o(s)`

=> moles `Al_2O_3(s)` is half as many moles as Al(s). => 0.833mole .=> `Al_2O_3(s)`

Convert to grams => 0.833 mole`Al_2O_3(s)`(102 g/mole) = 85g `Al_2O_3(s)`