How do you find the x and y intercept of #4x+y=4#?

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Answer 1 · 2017-04-26T17:14:02

See the solution process below:

y-intercept:

Substitute #0# for #x# and solve for #y#:

#4x + y = 4# becomes:

#(4 * 0) + y = 4#

#0 + y = 4#

#y = 4#

The y-intercept is #4# or #(0, 4)#

x-intercept:

Substitute #0# for #y# and solve for #x#:

#4x + y = 4# becomes:

#4x + 0 = 4#

#4x = 4#

#(4x)/color(red)(4) = 4/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = 1#

#x = 1#

The x-intercept is #1# or #(1, 0)#