Question

How do you factor and solve `x^2-4x=3`?

Answer 1

`x = 2 +-sqrt7`

Explanation:

`x^2 - 4 x = 3`

use completing a square or quadraric formulae to soive.
by using completing a square,
`(x -2)^2 - (-2)^2 =3`
`(x - 2)^2 = 3 +4 = 7`
`(x - 2) = +-sqrt7`
`x = 2 +-sqrt7`

therefore it factor is
`(x - (2+sqrt7))(x - (2-sqrt7))=0`