Question

Question #e2370

Answer 1

Once all the `"Ag"^"+""(aq)"` has been plated out as `"Ag(s)"`, there is nothing left to react with the `"Cu(s)"`.

Explanation:

The half-reactions are:

`color(white)(mmmmmmmmmmmmmmmmmmmmmmmm)E^@"/V""`
`2×["Ag"^"+""(aq)" + "e"^"–" → "Ag(s)"]; color(white)(mmmmmmmml)"+0.7994"`
`1×["Cu(s)" → "Cu"^"2+""(aq)" + "2e"^"-"]; color(white)(mmmmmmmm)"-0.337"`
`stackrel(————————————————————)(color(white)(mmll)"2Ag"^"+""(aq)" + "Cu(s)" → "2Ag"^"+""(s)" + "Cu"^"2+""(aq)"); stackrel(———)(0.4624)`

The `"Ag"^"+""(aq)"` oxidizes the `"Cu(s)"` to `"Cu"^"2+""(aq)"` and is itself reduced to `"Ag(s)"`, which plates out.

Once all the `"Ag"^"+""(aq)"` has been plated out as `"Ag(s)"`, there is nothing left to react with the `"Cu(s)"`, so the reaction stops.