How do you solve the system of equations #-8x + 3y = 7# and #13x - 3y = - 17#?
1 Answer
Apr 28, 2017
See explanation.
Explanation:
The starting system can be written as:
#{(-8x+3y=7),(13x-3y=-17) :}#
We can see that the coefficients of
#5x=-10 => x=-2#
Now if we substitute the calculated value of
#-8*(-2)+3y=7#
#16-3y=7#
#-3y=-9 => y=-3#
Finally we can write that the solution is: