How do you find the x and y intercept of #4x-3y+8=0#?

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Answer 1 · 2017-05-01T13:23:50

See the solution process below:

For the x-intercept:

Substitute #0# for #y# and solve for #x#:

#4x - 3y + 8 = 0# becomes:

#4x - (3 * 0) + 8 = 0#

#4x - 0 + 8 = 0#

#4x + 8 = 0#

#4x + 8 - color(red)(8) = 0 - color(red)(8)#

#4x + 0 = -8#

#4x = -8#

#(4x)/color(red)(4) = -8/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = -2#

#x = -2#

The x-intercept is #-2# or #(-2, 0)#

For the y-intercept:

Substitute #0# for #x# and solve for #y#:

#4x - 3y + 8 = 0# becomes:

#(4 * 0) - 3y + 8 = 0#

#0 - 3y + 8 = 0#

#-3y + 8 = 0#

#-3y + 8 - color(red)(8) = 0 - color(red)(8)#

#-3y + 0 = -8#

#-3y = -8#

#(-3y)/color(red)(-3) = (-8)/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))y)/cancel(color(red)(-3)) = 8/3#

#y = 8/3#

The y-intercept is #8/3# or #(0, 8/3)#