How do you find the roots, real and imaginary, of y=x^2 - 5/2x + 1/2 using the quadratic formula?

1 Answer
May 3, 2017

x=(5+-sqrt17)/4

Explanation:

If an equation is ax^2+bx+c=0
Then x=(-b+-sqrt(b^2-4ac))/(2a)
To solve this equation
You can judge by this pattern b^2-4ac
So 25/4-4*1*1/2>0
This result imply us exist 2 real roots you can find
Thus begin solving
x=((5/2)+-sqrt(25/4-4*2*1/2))/2
x=(5+-sqrt17)/4