Question

Question #c3e59

Answer 1

B. `"CH"_3"CH"_2"OH"` has eight covalent bonds.

Explanation:

A. `"HOCH"_2"CH"_2"OH"`

This compound has 1 `"C-C"` bond, 2 `"C-O"` bonds, 4 `"C-H"` bond, and 2 `"O-H"` bonds, for 9 covalent bonds.

B. `"CH"_3"CH"_2"OH"`

Ethanol

This compound has 1 `"C-C"` bond, 1 `"C-O"` bond, 5 `"C-H"` bonds, and 1 `"O-H"` bond, for a total of eight covalent bonds.

C. `"HOCOCOOH"`

This compound contains 1 `"C-C"` bond, 6 `"C-O"` bonds (each `"C=O"` counts as two covalent bonds), and 2 `"O-H"` bonds, for 9 covalent bonds.

D. `"HOCH"_2"COOH"`

This compound contains 1 `"C-C"` bond, 4 `"C-O"` bonds, 2 `"C-H"` bonds, and 2 `"O-H"` bonds, for 9 covalent bonds.

Answer 2

`B` is the correct option

Explanation:

We can use the following formula to determine the number of covalent bonds in a molecule.

`"Number of covalent bonds"=(x-y)/2`

where `x` is the total number of electrons required to fulfil the octet for atom other than hydrogen atom and doublet for hydrogen atom.

and `y` is the total number of valence electrons.

A) For compound `HOCH_2CH_2OH`

which consists of 2C ,2O and 6H ,we have

`x=2*8+2*8+6*2=44`

`y=2*4+2*6+6*1=26`

So `"Number of covalent bonds"=(x-y)/2=(44-26)/2=9`

B) For compound `CH_3CH_2OH`

which consists of 2C ,1O and 6H ,we have

`x=2*8+1*8+6*2=36`

`y=2*4+1*6+6*1=20`

So `"Number of covalent bonds"=(x-y)/2=(36-20)/2=8`

C) For compound `HOCOCOOH`

which consists of 2C ,4O and 2H ,we have

`x=2*8+4*8+2*2=52`

`y=2*4+4*6+2*1=34`

So `"Number of covalent bonds"=(x-y)/2=(52-34)/2=9`

D) For compound `HOCH_2COOH`

which consists of 2C ,3O and 4H ,we have

`x=2*8+3*8+4*2=48`

`y=2*4+3*6+4*1=30`

So `"Number of covalent bonds"=(x-y)/2=(48-30)/2=9`