How do you solve #x^2 – 3x = -6x – 1# using the quadratic formula?

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Answer 1 · 2017-05-03T16:46:01

#color(red)(x=(-3+sqrt5)/2=-0.382# to the nearest 3 decimal #
or

#color(red)(x=(-3-sqrt5)/2=-2.618# to the nearest 3 decimal places

#x^2-3x=-6x-1#

#x^2+3x+1=0#

#x=(-b+-sqrt(b^2-4ac))/(2a)#

#x=(-(3)+-sqrt((3^2)-4(1)(1)))/(2(1))#

#x=(-3+-sqrt(9-4))/2#

#x=(-3+-sqrt5)/2#

#color(red)(x=(-3+sqrt5)/2=-0.382# to the nearest 3 decimal places

or

#color(red)(x=(-3-sqrt5)/2=-2.618# to the nearest 3 decimal places