The force applied on a moving object with a mass of #2 kg # on a linear path is given by #F(x)=x^2+1 #. How much work would it take to move the object over #x in [0,2 ] #?

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Answer 1 · 2017-05-04T09:58:04

The work is #=4.67J#

The work is

work= force * distance

#dW=Fdx#

#dW=(x^2+1)dx#

#W=int_0^2(x^2+1)dx#

#=[x^3/3+x]_0^2#

#=(8/3+2)-(0)#

#=14/3#

#=4.67J#