A container with a volume of #35 L# contains a gas with a temperature of #480^o K#. If the temperature of the gas changes to #300 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-05-05T15:30:51

The volume is #=21.875L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

The initial volume is #V_1=35L#

The initial temperature is #T_1=480K#

The final temerature is #T_2=300K#

The final volume is

#V_2=T_2/T_1*V_1#

#=300/480*35#

#=21.875L#