Question #e6ee7

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Eddie
May 5, 2017

The power will be the energy per photon, # (hc)/lambda#, times the number, #n#, of photons emmitted each second:

#P = n (hc)/lambda#

#implies n = (P lambda)/(hc) = (330 xx 600*10^(-9))/(6.63*10^(-34) xx 3* 10^8) approx 10^(21) \ s^(-1) #

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