Question #80a54 Chemistry Electrochemistry Oxidation Numbers 1 Answer Professor Sam May 7, 2017 You have copied the question wrong. #VO_2# is a not an ion. It is a compound formed by the following reaction and compounds have a charge of 0. It forms #VO^(+2)# when dissolved in non-oxidising acids such as #HCl# #V_2O_5 + V_2O_3 → 4 VO_2# So actually the equation is #x + ((-2) + (-2)) = 0# #x + (-4) = 0# #x = 4# Answer link Related questions How do oxidation numbers relate to electron configuration? How do oxidation numbers relate to valence electrons? How do oxidation numbers vary with the periodic table? How do you calculate the oxidation number of an element in a compound? What is the oxidation number for sulfur? What is the oxidation number for carbon? What is the oxidation number for copper? What is the oxidation number for nitrogen? What is the oxidation number for oxygen? Why is the oxidation state of noble gas zero? See all questions in Oxidation Numbers Impact of this question 1831 views around the world You can reuse this answer Creative Commons License