How do you solve #x/3-x/4+5/6=1/2#?

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Answer 1 · 2017-05-08T13:02:57

Common base approach #x=-4#

Multiply first (x) term by 4, second term by 3, and third term by 2:

#(4x)/12 - (3x)/12 + 10/12#

which is equal to #6/12# (the second term on right hand side)

Now you have

#4x - 3x +10 = 6# after simplfying your 12s.

Or in other words,

#x + 10 = 6#

#x=-4#

This is your answer,

#x=-4#