Question

Question #a9c1d

Answer 1

No `y^2/2!=1/(2x^2y^4)`

Explanation:

`(cancel8^color(red)1cancelxy^8)/(cancel16^color(red)2cancelxy^6)=1/(2x^2y^4)`

simplify L.H.S.

`:.y^(8-6)/2`

`y^2/2!=1/(2x^2y^4)`