A ball with a mass of $360 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $8 (kg)/s^2$ and was compressed by $4/3 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-05-10T06:57:58

The height is $=2.0m$

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The spring constant is $k=8kgs^-2$

The compression is $x=4/3m$

The potential energy in the spring is

$PE=1/2*8*(4/3)^2=64/9J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

$PE_(ball)=64/9=0.36*9.8*h$

$h=64/9*1/(0.36*9.8)$

$=2.0m$

A ball with a mass of 360 g360 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 8 (kg)/s^28 (kg)/s^2 and was compressed by 4/3 m4/3 m when the ball was released. How high will the ball go?