How do you solve #\frac { 1} { 16} \sqrt { 12- x } = \frac { 1} { 4}#?

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Answer 1 · 2017-05-10T20:06:19

Isolate the square root, square both sides, then solve for x. Answer: #x=-4#

#1/16sqrt(12-x)=1/4#

First we want to isolate the square root by multiplying both sides by 16:

#16*1/16sqrt(12-x)=1/4*16#

#sqrt(12-x)=4#

Now we square both sides and solve for x:

#sqrt(12-x)^2=4^2#

#12-x=16#

#x=-4#

Therefore our answer is #x=-4#.