A gas occupies 12.3 at a pressure of 40.0 KPa. What is the volume when the pressure is increased to 60.0 KPa?

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Answer 1 · 2017-05-11T09:47:02

The volume is #=8.2u#, whatever the chosen units were to begin with...

We apply Boyle's Law at constant temperature and constant number of #"mol"#s:

#P_1V_1=P_2V_2#

The initial pressure is #P_1=40 kPa#

The initial volume is #V_1=12.3#

The final pressure is #60kPa#

The final volume is

#V_2=P_1/P_2*V_1#

#=40/60*12.3=8.2u#