How do you find the nature of the roots using the discriminant given 5 - 7x^2 + 2x = 057x2+2x=0?

1 Answer
May 11, 2017

Because the discriminant is 144>0, there are two real roots.

Explanation:

First, rewrite the formula in standard form, ax^2+bx+c=0ax2+bx+c=0
-7x^2+2x+5=07x2+2x+5=0

Note that
a=-7a=7
b=2b=2
c=5c=5

The discriminant is given as b^2-4acb24ac from the quadratic formula. The nature of the roots can be determined by knowing the three rules for the discriminant.

  • If b^2-4ac=0b24ac=0, then there is one solution.
  • If b^2-4ac>0b24ac>0, then there are two solutions.
  • If If b^2-4ac<0b24ac<0, then there are no real solutions.

Plugging aa, bb, and cc from above into the discriminant gives
(2)^2-4(-7)(5)=4+28(5)=144(2)24(7)(5)=4+28(5)=144

Because the discriminant is 144>0, there are two solutions. The parabola has roots on the xx-axis at two points. Finally, because the coefficient a=-7a=7 is negative, the parabola opens downward, as in the following graph:

graph{y=-7x^2+2x+5 [-1.3, 1.5, -2, 5.5]}