Question

The pressure exerted on 800mL of a gas is decreased from 300 kPa to 198 kPa. What is the new volume of the gas if the temp remains constant?

Answer 1

`V_2=1200*mL........`

Explanation:

At constant temperature, `PV=k`, for a fixed amount (mass) of gas. This is old Boyle's Law:

Since `PV=k`, `P_1V_1=P_2V_2`

`V_2=(P_1V_1)/P_2=(300*kPaxx800*mL)/(198*kPa)=??*mL`. A good question in that you don't have to use a calculator.........