Find the partial derivatives of # u=xlny+ylnz+zlnx # ?
1 Answer
May 12, 2017
We have:
# u=xlny+ylnz+zlnx #
Remember when partially differentiating that we differentiate wrt the variable in question whilst treating the other variables as constant. And so the partial derivatives are:
# (partial u)/(partial x) = u_x = lny+z/x #
# (partial u)/(partial y) = u_y = x/y+lnz #
# (partial u)/(partial z) = u_z = y/z+lnx #
