Question

How many mL of 0.200 M HCI are needed to neutralize 20.0 mL of 0.150 M `Ba(OH)_2`?

Answer 1

Approx. `-=60*mL`

Explanation:

We use the relationship: `"Moles of stuff"/"Volume of solution"="Molarity"`.

There are `2xx20xx10^-3*Lxx0.150*mol*L^-1=6.00xx10^-3*mol` `Ba(OH)_2`, and this is neutralized according to the following equation:

`Ba(OH)_2(s) + 2HCl(aq)rarrBaCl_2(aq) + 2H_2O(l)`

Given the `"STOICHIOMETRY"`, we need 2 equiv of hydrochloric acid, and given `0.200*mol*L^-1` `HCl(aq)` we need a volume of..........

`(6.00xx10^-3*cancel(mol)xx2)/(0.200*cancel(mol)*L^-1)=0.0600*L`

`-=60*mL`