How do you evaluate the limit of $lim (-4x^2+2x-5)$ as $x->2$ ?

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Answer 1 · 2017-05-13T17:00:41

Substitution. Answer $-17$

Question: Evaluate $lim_(x->2)(-4x^2+2x-5)$

By substitution, we get:
$lim_(x->2)(-4x^2+2x-5)$

$=-4(2^2)+2(2)-5$

$=-17$

How do you evaluate the limit of lim (-4x^2+2x-5)lim (-4x^2+2x-5) as x->2x->2?