Question

What is the Cartesian form of `(-17,(-3pi)/6))`?

Answer 1

`(0,17)`

Explanation:

To write a polar point into cartesian form, we convert it into the parametric form using these equations:

`x=rcostheta`
`y=rsintheta`

`r=-17` and `theta=(-3pi)/6` Plug into these equations:

`x=-17cos(-pi/2)=0`
`y=-17sin(-pi/2)=17`

So we have `x=0` and `y=17`. Write this as a point:

`(0,17)`