How do you simplify the expression #((qr^2s)/(3r^4))^-3# using the properties?

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Answer 1 · 2017-05-15T22:36:36

See below.

Before we deal with the exponent, let's deal with the fraction.

We know that #r^a/r^b=r^(a-b)#

So, #r^2/r^4=1/r^2#

The expression becomes:

#((qs)/(3r^2))^-3#

When we have a negative power in the exponent, we flip the fraction.

#((3r^2)/(qs))^3#

Now we cube everything.

#(27r^6)/(q^3s^3)#