Question

How do you solve `3(2x+7)=27` using the distributive property?

Answer 1

`x=1`

Explanation:

`"distribute the bracket on the left side"`

`rArr6x+21=27`

`"subtract 21 from both sides"`

`6xcancel(+21)cancel(-21)=27-21`

`rArr6x=6`

`"divide both sides by 6"`

`(cancel(6) x)/cancel(6)=6/6`

`rArrx=1`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`3(2xx1+7)=3xx9=27=" right side"`

`rArrx=1" is the solution"`