How do you write an equation of a line that passes through points (4,2), (-2,-4)?
1 Answer
May 16, 2017
Explanation:
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the t-intercept.
#"to calculate m use the "color(blue)"gradient formula"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#
where# (x_1,y_1),(x_2,y_2)" are 2 coordinate points"#
#"the 2 points are " (x_1,y_1)=(4,2),(x_2,y_2)=(-2,-4)#
#rArrm=(-4-2)/(-2-4)=(-6)/(-6)=1#
#rArry=x+blarr" partial equation"#
#"to find b, substitute either of the 2 given points into "#
#"the partial equation"#
#"using " (4,2)#
#2=4+brArrb=-2#
#rArry=x-2larrcolor(red)" in slope-intercept form"#
graph{x-2 [-10, 10, -5, 5]}