Question

In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 mL of HCl to completely neutralize the acid?

Answer 1

Well, you need to add `45.0*mL` of your standard `NaOH` solution precisely...........

Explanation:

And first we represent the reaction by an equation:

`HCl(aq) + NaOH(aq) rarr NaCl(aq) + H_2O(l)`

And thus there is `1:1` `"stoichiometry"`.

We use the relationship `"Molarity"="Moles of solute"/"Volume of solution"`.

What is the volume of the solution at equivalence?