What is the equation of the line perpendicular to #y=-1/5x # that passes through # (7,4) #?

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Answer 1 · 2017-05-17T05:54:22

#y=5x-31#

Given -

#y=-1/5x#

Slope of the given line

#m_1=-1/5#

The two line are perpendicular

Slope of the second line #m_2=1/(m_1) xx-1=-5 xx -1 =5#

Second line passes through the point #(7, 4)#

Equation of the second line

#y=mx+c#
#4=(5 xx 7)+c#
#4=35+c#

#c=4-35=-31#

#y=5x-31#