Question

How do you calculate the pH of 0.075M KOH?

Answer 1

`pH=12.88`

Explanation:

We know `(i)` that `pH+pOH=14` in aqueous solution under standard conditions...........

We also know `(ii)` that `pOH=-log_10[HO^-]`

`=-log_10(0.075)=-(-1.12)=+1.12`.

And so `pH=14-pOH=12.88`