A triangle has corners at points A, B, and C. Side AB has a length of #9 #. The distance between the intersection of point A's angle bisector with side BC and point B is #6 #. If side AC has a length of #8 #, what is the length of side BC?

1 Answer
May 19, 2017

#34/3 approx 11.33#

Explanation:

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Consider this image where #AD# is the angle bisector of #A#.

Triangles have a property related to angle bisectors called the angle bisector theorem :-

That if #AD# is the angle bisector of #A# then, #color(red)[(AB)/(AC) = (BD)/(CD)]#, i.e. an angle bisector divides the opposite side in the ratio if the adjacent sides.

For proofs of this theorem visit this link.
I have gone through both the proofs and found them to be correct.

You can also watch this video.

Now, in this question,
#AB = 9#
#AC = 8#
#BD = 6#

#=> 9/8 = 6 / (CD)#

#=> CD = 6*8/9 = 16/3#

#=> BC = BD + CD = 6 + 16/3 = (18+16)/3 = 34/3 approx 11.33#