Question #50b52

1 Answer
A08
May 19, 2017

Farmer's Speed #=10/40=0.25ms^-1#

Let the farmer be at the origin initially.
Total time of travel #=60xx2+20=120+20=140sec#
Total distance traveled#=0.25xx140=35m#

Field being square of side #=10m#
#:.#Total number of sides traveled in the given time#=3.5#

We know that after traveling #4# sides farmer would be back at the origin.
As such magnitude of displacement after given time #=4-3.5=1/2 side#
#=1/2xx10=5m#

Related questions
See all questions in Vector Operations
Impact of this question
1622 views around the world
You can reuse this answer
Creative Commons License