What is the oxidation number of fluorine in #HF#?

1 Answer
anor277
May 20, 2017

We got #stackrel(-I)F#

Explanation:

Fluorine is the most electronegative atom in the entire Periodic Table, so it always gets assigned the other electron in the covalent bond of #H-F# to give #stackrel(-I)F# and #stackrel(+I)H#. What are the oxidation numbers of oxygen and fluorine in the (real) molecule, #OF_2#?

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