How do you solve #x+7/12=2#?

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Answer 1 · 2017-05-20T16:00:01

#x = frac(17)(12)#

We have: #x + frac(7)(12) = 2#

Let's subtract #frac(7)(12)# from both sides of the equation:

#Rightarrow x + frac(7)(12) - frac(7)(12) = 2 - frac(7)(12)#

#Rightarrow x = 2 - frac(7)(12)#

#Rightarrow x = frac(24)(12) - frac(7)(12)#

#therefore x = frac(17)(12)#

Therefore, the solution to the equation is #x = frac(17)(12)#.