Question

How do you find the range of `b(x)=-x^2` for the domain (-2,0,3,8)?

Answer 1

R{0,-4,-9,-64}

Explanation:

Plug in each x into the function.
The value of b(x) will be in your range.

`b(-2) = -4`
`b(0) = 0`
`b(3) = -9`
`b(8) = -64`

Therefore the range is {-4,0,-9,-64}, rearranged to {0,-4,-9,-64}.